First clear solution for Acceptable Password II by maxalex324 - python coding challenges

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First solution in Clear category for Acceptable Password II by maxalex324

def is_acceptable_password(password):
    return  (len(password)>6)

def is_acceptable_password(password):
    return (len(password)>6)*any([i.isdigit() for i in password])

May 19, 2020

Comments:

dannystaple on Aug. 10, 2020, 1:14 p.m.
<p>Not sure about using multiply instead of "and". It will work, but looks odd.</p>

Strings Theory

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