Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Acceptable Password II by libertypi
def is_acceptable_password(password: str) -> bool:
# your code here
return len(password) > 6 and any(i.isdigit() for i in password)
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
print("Coding complete? Click 'Check' to earn cool rewards!")
June 9, 2020
Comments:
