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Direct solution solution in Clear category for Acceptable Password II by amandel
def is_acceptable_password(p):
return len(p)>5 and any(x.isdigit() for x in p)
if __name__ == "__main__":
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("muchlonger") == False
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
print("Coding complete? Click 'Check' to earn cool rewards!")
July 6, 2022
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