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one line solution in Clear category for Acceptable Password II by WuYuFFFan
from operator import *
def is_acceptable_password(password: str) -> bool:
return len(password)>=6 if any([each.isdigit() for each in password]) else False
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
print("Coding complete? Click 'Check' to earn cool rewards!")
Aug. 6, 2020
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