First clear solution for Acceptable Password II by H0r4c3 - python coding challenges

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First solution in Clear category for Acceptable Password II by H0r4c3

# Taken from mission Acceptable Password I
import re

def is_acceptable_password(password: str) -> bool:
    if len(password) > 6 and re.findall('\d', password):
        return True
    else:
        return False


if __name__ == '__main__':
    print("Example:")
    print(is_acceptable_password('short'))



if __name__ == "__main__":
    # These "asserts" are used for self-checking and not for an auto-testing
    assert is_acceptable_password("short") == False
    assert is_acceptable_password("muchlonger") == False
    assert is_acceptable_password("ashort") == False
    assert is_acceptable_password("muchlonger5") == True
    assert is_acceptable_password("sh5") == False
    print("Coding complete? Click 'Check' to earn cool rewards!")

Nov. 15, 2021

Comments:

ozg on Aug. 26, 2022, 9:55 p.m.
<p>very good solution with re module. I like the regular expressions. I have two comments. First you can use re.search instead of re.findall. Second you don't need if and else conditionals, you can directly return the boolean expression in the if condition.</p>

H0r4c3 on Aug. 27, 2022, 10:17 a.m.
<p>Correct! It is enough to find the first one (using re.search). And is shorter to return the boolean expression.</p>

Strings Theory

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