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len + any + map solution in Clear category for Acceptable Password II by CDG.Axel
# Taken from mission Acceptable Password I
def is_acceptable_password(password: str) -> bool:
# your code here
return len(password) > 6 and any(map(str.isdigit, password))
#return len(password) > 6 and sum([i.isdigit() for i in password]) > 0
if __name__ == "__main__":
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("muchlonger") == False
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
print("Coding complete? Click 'Check' to earn cool rewards!")
Sept. 2, 2021
